Find the discriminant of the following quadra | vedclass

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Question

(A) The given quadratic equation is $x^{2} = 9$,which can be written in the standard form $ax^{2} + bx + c = 0$ as $x^{2} + 0x - 9 = 0$.Here,$a = 1$,$

Vedclass · Accepted Answer

Discriminant = $36$,Roots are real,rational,and distinct.

Vedclass · Answer

(A) The given quadratic equation is $x^{2} = 9$,which can be written in the standard form $ax^{2} + bx + c = 0$ as $x^{2} + 0x - 9 = 0$.Here,$a = 1$,$b = 0$,and $c = -9$.The discriminant $D$ is given by the formula $D = b^{2} - 4ac$.Substituting the values,we get $D = (0)^{2} - 4(1)(-9) = 0 + 36 = 36$.Since $D > 0$ and $D$ is a perfect square $(6^{2} = 36)$,the roots of the equation are real,rational,and distinct.

Part $I$	Part $II$
$1.$ The discriminant of $x^{2}+5x+6=0$	$a. 1$
$2.$ The discriminant of $x^{2}+5x+4=0$	$b. 9$
$3.$ The discriminant of $x^{2}+4x+3=0$	$c. 4$
$4.$ The discriminant of $x^{2}+6x+5=0$	$d. 16$

Find the discriminant of the following quadratic equation and hence determine the nature of the roots of the equation: $x^{2} = 9$.

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